Y =(9x ^ 2 + 5)(x-1)の標準形式は何ですか?

Y =(9x ^ 2 + 5)(x-1)の標準形式は何ですか?
Anonim

回答:

#y = 9x ^ 3-9x ^ 2 + 5x-5#

説明:

#色(白)(aaaaaaaaaaaaaaa)##9x ^ 2 + 5#

#色(白)(aaaaaaaaaaaaaaa)##x-1#

#色(白)(aaaaaaaaaaaaaaa)##---#

#色(白)(aaaaaaaaaaaaaaa)##9x ^ 3 + 5x#

#色(白)(aaaaaaaaaaaaaaaa)##-9x ^ 2-5#

#色(白)(aaaaaaaaaaaaaaaa)##-----#

#色(白)(aaaaaaaaaaaaaaa)##9x ^ 3-9x ^ 2 + 5x-5#