どうやって(-6x ^ 4-3x ^ 3-2x ^ 2-4x-7)/(x ^ 2 + 3)に分けますか?

どうやって(-6x ^ 4-3x ^ 3-2x ^ 2-4x-7)/(x ^ 2 + 3)に分けますか?
Anonim

回答:

#色(青)(( - 6x ^ 4-3x ^ 3-2x ^ 2-4x-7)/(x ^ 2 + 3)= - 6x ^ 2-3x + 16 +(5x-55)/(x ^ 2 + 3))#

説明:

#( - 6x ^ 4-3x ^ 3-2x ^ 2-4x-7)/(x ^ 2 + 3)#

ロングディビジョン法:

# "" "" "" "" "" "下線(-6x ^ 2-3x + 16" "" "" "" "" "" "" "" "" "" ""#

#x ^ 2 + 0 * x + 3 |〜-6x ^ 4-3x ^ 3-2x ^ 2-4x-7#

# "" "" "" "" "" "下線(-6x ^ 4 + 0 * x ^ 3-18x ^ 2" "" "" ")#

# "" "" "" "" "" "" "" "-3x ^ 3 + 16x ^ 2-4x-7#

# "" "" "" "" "" "" "" "下線(-3x ^ 3 + 0 * x ^ 2-9x)#

# "" "" "" "" "" "" "" "" "" "16x ^ 2 + 5x-7#

# "" "" "" "" "" "" "" "" "" ""下線(16x ^ 2 + 0 * x + 48)#

# "" "" "" "" "" "" "" "" "" "" "" "" + 5x-55 larr#残り

答え

#色(青)(( - 6x ^ 4-3x ^ 3-2x ^ 2-4x-7)/(x ^ 2 + 3)= - 6x ^ 2-3x + 16 +(5x-55)/(x ^ 2 + 3))#