回答:
#f '(x)=(1 /(ln((x + 4)/(ln(x ^ 2 + 4)))))((1)/((x + 4)))((((x) ^ 2 + 4)(ln(x ^ 2 + 4)) - (2x ^ 2 + 4x))/(((x ^ 2 + 4)(ln(x ^ 2 + 4))))#
説明:
#f '(x)=(1 /(ln((x + 4)/(ln(x ^ 2 + 4)))))(1 /((x + 4)/(ln(x ^ 2 + 4)) (((1)(ln(x ^ 2 + 4)) - (x + 4)(1)/((x ^ 2 + 4))(2x))/((ln(x ^)))))) 2 + 4)))^ 2)#
#f '(x)=(1 /(ln((x + 4)/(ln(x ^ 2 + 4)))))(ln(x ^ 2 + 4)/((x + 4))) 。(((ln(x ^ 2 + 4) - (2x ^ 2 + 4x)/((x ^ 2 + 4)))/(((ln(x ^ 2 + 4)))^ 2)#
#f '(x)=(1 /(ln((x + 4)/(ln(x ^ 2 + 4)))))(キャンセル(ln(x ^ 2 + 4))/((x + 4) )))。((((x ^ 2 + 4)(ln(x ^ 2 + 4)) - (2x ^ 2 + 4x))/((x ^ 2 + 4)(ln(x ^ 2 + 4)) )^キャンセル(2)))#
#f '(x)=(1 /(ln((x + 4)/(ln(x ^ 2 + 4)))))((1)/((x + 4)))((((x) ^ 2 + 4)(ln(x ^ 2 + 4)) - (2x ^ 2 + 4x))/(((x ^ 2 + 4)(ln(x ^ 2 + 4))))#