回答: の製品 #(x ^ 2-1)/(x + 1)# そして #(x + 3)/(3x-3)# です #(x + 3)/ 3# 説明: #(x ^ 2-1)/(x + 1)xx(x + 3)/(3x-3)# = #((x + 1)(x-1))/(x + 1)xx(x + 3)/(3(x-1))# = #(cancel((x + 1))cancel((x-1)))/ cancel((x + 1))xx(x + 3)/(3(cancel(x-1)))# = #(x + 3)/ 3#